range of sqrt(6x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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축 16x²+25y²=100

Solution

주축 a=52 , 반원축 b=2

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16x²+25y²=100

타원 표준 방정식

(x−h)²a² +(y−k)²b² =1 는 타원 표준 방정식이다
중심을 잡고 (h, k) 그리고 a, b 반주요 축과 반주요 축이다

다시 쓰다 16x²+25y²=100 표준타원방정식의 형태로

(x−0)²(52 )² +(y−0)²2² =1

따라서 타원 속성은 다음과 같습니다

(h, k)=(0, 0), a=52 , b=2

a>b 그러므로 a 는 반장축이며 b 반지름 축입니다

중심이 있는 타원 (h, k)=(0, 0), a=52 , b=2

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

range of sqrt(6x)

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