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범위 (x^3-2x^2-3x)/(x^2-4)

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역 라플라스 4x−7x²+5x

Solution

−75 H(t)+275 e^−5t

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L⁻¹{4x−7x²+5x }

4x−7x²+5x 의 부분적인 부분을 취하라: −75x +275(x+5)

=L⁻¹{−75x +275(x+5) }

역 라플라스 변환의 선형성 특성 사용:
함수의 경우f(s), g(s) 및 상수 a, b: L⁻¹{a·f(s)+b·g(s)}=a·L⁻¹{f(s)}+b·L⁻¹{g(s)}

=−L⁻¹{75x }+L⁻¹{275(x+5) }

L⁻¹{75x }: 75 H(t)

L⁻¹{275(x+5) }: 275 e^−5t

=−75 H(t)+275 e^−5t

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안녕, 질문하다 역 라플라스 4x−7x²+5x 또는 아래를 선택하세요

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

범위 (x^3-2x^2-3x)/(x^2-4)

Solution

Solution steps

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