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역함수 20((x-3)(x+4))/((x-3)^2(x-5))

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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범위 20(x−3)(x+4)(x−3)²(x−5)

Solution

f(x)≤ −30√7−80 or 30√7−80≤ f(x)<0 or f(x)>0

Interval Notation

(−∞ , −30√7−80]∪ [30√7−80, 0)∪(0, ∞ )

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Solution steps

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함수 범위 정의

함수가 정의되는 종속 변수의 값 집합

함수 범위는 역함수의 결합 영역이다

다음의 역함수를 구하라: 20(x−3)(x+4)(x−3)²(x−5)

의 역 20(x−3)(x+4)(x−3)²(x−5) : 4x+10+√x²+160x+100x , 4x+10−√x²+160x+100x

4x+10+√x²+160x+100x , 4x+10−√x²+160x+100x

각 역함수의 영역 찾기

도메인 4x+10+√x²+160x+100x : x≤ −30√7−80 or 30√7−80≤ x<0 or x>0

도메인 4x+10−√x²+160x+100x : x≤ −30√7−80 or 30√7−80≤ x<0 or x>0

간격 결합

f(x)≤ −30√7−80 or 30√7−80≤ f(x)<0 or f(x)>0

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도메인 20(x−3)(x+4)(x−3)²(x−5)

역함수 20(x−3)(x+4)(x−3)²(x−5)

가로채기 20(x−3)(x+4)(x−3)²(x−5)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

역함수 20((x-3)(x+4))/((x-3)^2(x-5))

Solution

Solution steps

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Number Line

Graph

1	−1	0
1	0	1
0	−1	1

1	1	1	2
1	0	1	−1
0	−1	−2	1
0	2	0	2