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정점 x^2-y^2=1

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f(x)=6x7 · 4x3

Solution

Domain: −∞ <x<∞

Range: f(x)≥ 0

X 가로채기: (0, 0), Y 가로채기: (0, 0)

Vertex: 극히 적은 양 (0, 0)

Inverse: √14√x4 , −√14√x4

Interval Notation

Domain: (−∞ , ∞ )

Range: [0, ∞ )

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Solution steps

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도메인 6x7 · 4x3 : −∞ <x<∞

범위 6x7 · 4x3 : f(x)≥ 0

축 가로채기 포인트 6x7 · 4x3 : X 가로채기: (0, 0), Y 가로채기: (0, 0)

꼭짓점 6x7 · 4x3 : 극히 적은 양 (0, 0)

의 역 6x7 · 4x3 : √14√x4 , −√14√x4

Solve instead

ddx (6x7 · 4x3 )

동등성 6x7 · 4x3

대칭 6x7 · 4x3

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안녕, 질문하다 f(x)=6x7 · 4x3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

정점 x^2-y^2=1

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