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horizontal tangent of 2x^3+3x^2+9

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horizontal tangent 2x³+3x²+9

Solution

y=10, y=9

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Horizontal tangent definition

The horizontal tangent shows where the function has a slope of zero.

Critical Points of 2x³+3x²+9: x=−1, x=0

Plug into function to get y-values:: (−1, 10), (0, 9)

(−1, 10), (0, 9)

Therefore, the horizontal tangents are:

y=10, y=9

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domain 2x³+3x²+9

range 2x³+3x²+9

intercepts 2x³+3x²+9

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

horizontal tangent of 2x^3+3x^2+9

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