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parity -5x+e^x

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중심 4x²−9y²−48x−72y+108=0

Solution

(6, −4)

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4x²−9y²−48x−72y+108=0

하이퍼볼라 표준 방정식

(y−k)²a² −(x−h)²b² =1 아래를 향한 쌍곡선에 대한 표준 방정식이다
중심을 잡고(h, k), 반축 a 및 반축 b.

다시 쓰다 4x²−9y²−48x−72y+108=0 표준 쌍곡선 방정식의 형태로

(y−(−4))²(2√3)² −(x−6)²(3√3)² =1

따라서 하이퍼볼라의 속성은 다음과 같다:

(h, k)=(6, −4), a=2√3, b=3√3

그리고 그 중심은:

(6, −4)

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안녕, 질문하다 중심 4x²−9y²−48x−72y+108=0 또는 아래를 선택하세요

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

parity -5x+e^x

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