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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

Solutions > Functions Slope & Intercepts Calculator >

역함수 sec^2(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

π

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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Steps Examples

Generated by AI

대각화 (

6	−1
2	3

)

Solution

P=(

1	1
1	2

), D=(

5	0
0	4

), P⁻¹=(

2	−1
−1	1

)

Show Steps

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Solution steps

One step at a time

(

6	−1
2	3

)

행렬 대각화

행렬A가역 행렬이 존재할 경우 대각화할 수 있습니다P및 대각 행렬D그런 식으로A=PDP⁻¹

다음에 대한 고유값 찾기 (

6	−1
2	3

): λ=5, λ=4

대각행렬 D 고유값으로 구성됩니다:

D=(

5	0
0	4

)

다음에 대한 고유 벡터 찾기(

6	−1
2	3

): (

1

1

), (

1

2

)

다음에서 고유값에 해당하는 고유 벡터 D 칼럼을 구성하다P :

P=(

1	1
1	2

)

P⁻¹ 찾다 : (

2	−1
−1	1

)

다음을 확인합니다 A=PDP⁻¹

PDP⁻¹ 해결 : (

6	−1
2	3

)

P=(

1	1
1	2

), D=(

5	0
0	4

), P⁻¹=(

2	−1
−1	1

)

Functions Slope & Intercepts Examples

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6	−1
2	3

) 또는 아래를 선택하세요

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