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4y′′−6y′+7y=0
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Solution
y=e3t4(c1cos(√19t4)+c2sin(√19t4))
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행렬 고유 벡터
허락하다 A 제곱행렬이다, η벡터와 λ만족시키는 스칼라 Aη=λη, 그렇다면 η는 의 고유 벡터이다A그리고 λ그것과 관련된 고유값이다