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가로채기 6ln(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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점근점 y²25 −x²9 =1

Solution

y=5x3 , y=−5x3

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하이퍼볼라 점근점

점근점은 쌍곡선이 다음과 같이 되는 경향이 있는 선이다 ±∞
상향 쌍곡선의 경우 점근은 다음과 같다 y=±ab (x−h)+k

y=± ab (x−h)+k

하이퍼볼라 속성 계산

y²25 −x²9 =1: 업다운 하이퍼볼라 (h, k)=(0, 0), a=5, b=3

y=53 (x−0)+0, y=−53 (x−0)+0

다듬다

y=5x3 , y=−5x3

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안녕, 질문하다 점근점 y²25 −x²9 =1 또는 아래를 선택하세요

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

가로채기 6ln(x)

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