정점 (-3x^2-2x+6)/5

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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섬디프 ddx ((x+2)²)

Solution

2x+4

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Solution steps

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∫ sin²(θ)dθ

삼각성을 사용하여 다시 쓰기

=∫ 1−cos(2θ)2 dθ

정수를 빼라: ∫a·f(x)dx=a·∫f(x)dx

=12 · ∫ 1−cos(2θ)dθ

합계 규칙 적용: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx

=12 (∫ 1dθ−∫ cos(2θ)dθ)

∫ 1dθ=θ

∫ cos(2θ)dθ=12 sin(2θ)

=12 (θ−12 sin(2θ))

솔루션에 상수 추가

=12 (θ−12 sin(2θ))+C

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안녕, 질문하다 섬디프 ddx ((x+2)²) 또는 아래 옵션 중에서 선택하세요

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

정점 (-3x^2-2x+6)/5

Solution

Solution steps

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