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gcd 1/3 x^7, 2/3 x^8, 4/3 x^4, 1/3 x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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고유값 (

1	2	3
4	5	6
7	2	9

)

Solution

λ≈ −1.03868…, λ≈ 2.57409…, λ≈ 13.46458…

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(

1	2	3
4	5	6
7	2	9

)

행렬 고유값

허락하다 A 제곱행렬이다, η 벡터와 λ 만족시키는 스칼라 Aη=λη,
그렇다면 λ 고유 벡터와 관련된 고유 값이라고 합니다 η of A

의 고유값은 다음과 같다 A 특성 방정식의 근이다 det(A−λ I)=0

det((

1	2	3
4	5	6
7	2	9

)−λ(

1	0	0
0	1	0
0	0	1

)): −λ³+15λ²−18λ−36

−λ³+15λ²−18λ−36=0 해결 : λ≈ −1.03868…, λ≈ 2.57409…, λ≈ 13.46458…

고윳값은 다음과 같습니다:

λ≈ −1.03868…, λ≈ 2.57409…, λ≈ 13.46458…

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

gcd 1/3 x^7, 2/3 x^8, 4/3 x^4, 1/3 x

Solution

Solution steps

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